x^2+y^2-6/5x+9/25-9=0

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Solution for x^2+y^2-6/5x+9/25-9=0 equation: 


x in (-oo:+oo)

t_1 = y^2-9+9/25

t_1+x^2-6/5*x = 0

t_1+x^2-6/5*x = 0

DELTA = (-6/5)^2-(1*4*t_1)

DELTA = 36/25-4*t_1

36/25-4*t_1 = 0

36/25-4*t_1 = 0 // - 36/25

-4*t_1 = -36/25 // : -4

t_1 = -36/25/(-4)

t_1 = 9/25

DELTA = 0  <=>  t_2 = 9/25

x = 6/5/(1*2) i t_1 = 9/25

x = 3/5 i t_1 = 9/25

( x = ((36/25-4*t_1)^(1/2)+6/5)/(1*2) or x = (6/5-(36/25-4*t_1)^(1/2))/(1*2) ) i t_1 > 9/25

( x = ((36/25-4*t_1)^(1/2)+6/5)/2 or x = (6/5-(36/25-4*t_1)^(1/2))/2 ) i t_1 > 9/25

t_1-9/25 > 0

t_1-9/25 > 0 // + 9/25

t_1 > 9/25

x in { 3/5, ((36/25-4*(y^2-9+9/25))^(1/2)+6/5)/2, (6/5-(36/25-4*(y^2-9+9/25))^(1/2))/2 }

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